-3[2-(13z+2)]=2+(9z+1)

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Solution for -3[2-(13z+2)]=2+(9z+1) equation:


Simplifying
-3[2 + -1(13z + 2)] = 2 + (9z + 1)

Reorder the terms:
-3[2 + -1(2 + 13z)] = 2 + (9z + 1)
-3[2 + (2 * -1 + 13z * -1)] = 2 + (9z + 1)
-3[2 + (-2 + -13z)] = 2 + (9z + 1)

Combine like terms: 2 + -2 = 0
-3[0 + -13z] = 2 + (9z + 1)
-3[-13z] = 2 + (9z + 1)

Remove brackets around [-13z]
-3 * -13z = 2 + (9z + 1)

Multiply -3 * -13
39z = 2 + (9z + 1)

Reorder the terms:
39z = 2 + (1 + 9z)

Remove parenthesis around (1 + 9z)
39z = 2 + 1 + 9z

Combine like terms: 2 + 1 = 3
39z = 3 + 9z

Solving
39z = 3 + 9z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-9z' to each side of the equation.
39z + -9z = 3 + 9z + -9z

Combine like terms: 39z + -9z = 30z
30z = 3 + 9z + -9z

Combine like terms: 9z + -9z = 0
30z = 3 + 0
30z = 3

Divide each side by '30'.
z = 0.1

Simplifying
z = 0.1

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